From: max@athealey.com.au   
      
   Cool thank you very much !!   
   "Henning"  wrote in message   
   news:4498038a$0$28494$57c3e1d3@news3.bahnhof.se...   
   > Yes, yes and yes   
   >   
   > You might have to use comm1.output = Chr$(&HB1) if the port is opened in   
   > Text mode.   
   >   
   > /Henning   
   >   
   > "Max Healey"  skrev i meddelandet   
   > news:4497b823$0$22364$afc38c87@news.optusnet.com.au...   
   >> I have written a number of applications that control various bits of   
   >> hardware via serial data. using VB6 and the comm. control   
   >>   
   >> now some one has asked me to do one for a specific piece of equipment,   
   >> the   
   >> protocol calls for 9600 8 N 1 all cool there,   
   >>   
   >> Then it specifies the following   
   >>   
   >> Baud Rate        9600   
   >> Startbit             Low   
   >> 8 Data Bits       Least Significant Bit first   
   >> No Parity          N/A   
   >> Stop Bit            High   
   >>   
   >> It also states that "the unit will sample the value on the third forth   
   >> and   
   >> fifth bits the value accepted is the value that was seen in two of the   
   > three   
   >> samples."   
   >>   
   >> Then there is a list of hex commands eg 11 do this B2 do that.   
   >>   
   >>   
   >> My questions are as follows.   
   >>   
   >> 1: Am I correct in assuming the comm. control will take care of the start   
   >> and stop bits ?   
   >>   
   >> 2: From the above would I be correct in assuming that all I need to do is   
   >> send B2 (for example) to the unit 3 times to get it to work   
   >>   
   >> EG:   
   >>     comm1.output = &HB1   
   >>   
   >> will the comm. control output that lsb first?   
   >>   
   >> I know I will have to do some testing but am looking for some one to   
   > confirm   
   >> or otherwise that I am on the right track   
   >>   
   >> Thanks in advance.   
   >>   
   >>   
   >> Max   
   >>   
   >>   
   >>   
   >>   
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