From: antony.clements@optusnet.com.au   
      
   if stream1 has a value of 1a2b3c4d i want bytearray() to return the asc   
   value of the string. the only way i know how to do this is take each   
   character convert to ascii and then place in a string and then place the   
   string in bytearray(). i'm looking for a simpler way. var1 and var2 are   
   always returning the value of 1306840 regardless. bytearray() will return   
   1a2b3c4d. i am copying the bytearray variables to long variables. the   
   problem will be solved once var1 and var2 are correct values.   
      
   "Dean Earley"  wrote in message   
   news:45d438c9$0$22115$db0fefd9@news.zen.co.uk...   
   > Antony Clements wrote:   
   >> i modified the code after i posted this, it no longer throws up an error   
   >> but it still doesn't work correctly.   
   >>   
   >>  dim var1 var2 and var3 as long   
   >>   
   >> ReDim IVbytearray(0 To 7)   
   >> ReDim IVbytearray2(0 To 7)   
   >   
   > These are redundant as they are replaced in the next block.   
   >   
   >> bytearray() = Mid(stream1, b, 8)   
   >> bytearray2() = Mid(stream2, c, 8) 'a messagebox here proves that at this   
   >> point, the data held in bytearray() is different than the data held in   
   >> bytearray2()   
   >   
   > This copies a UNICODE string into the byte array.   
   > This will be 16 bytes, every other one being a null character.   
   >   
   > If you want each character as an item in the array, then you want:   
   > bytearray = StrConv(string, vbFromUnicode)   
   >   
   >> var1 = bytearray()   
   >> var2 = bytearray2() 'this is where the problem is as var2 returns the   
   >> same value as var1 even though the value in bytearray() is different to   
   >> the value in bytearray2().   
   >   
   > From the code below, you can't join them up like this.   
   > You will need to do the arithmetic manually (shifting and adding) or   
   > copymemory from the byte array to a long.   
   > Bear in mind that you can only fit 4 bytes in a long...   
   >   
   >> Call CopyMemory(var1, var1 Xor var2, 8)   
   >> Call CopyMemory(var1, var1 Xor var3, 8)   
   >   
   > Be VERY careful as longs are still only 4 bytes.   
   > you WILL be corrupting memory with this code.   
   >   
   >> now here is the problem. even though the data source for bytearray() and   
   >> bytearray2() are different, for some reason or other they both have the   
   >> same value. var2 needs to be a value from the second data source. i hope   
   >> this is a clear indication of what i am trying to do.   
   >   
   > It still doesn't explain what you have and what results you want at the   
   > end...   
   >   
   > --   
   > Dean Earley (dean.earley@icode.co.uk)   
   > i-Catcher Development Team   
   >   
   > iCode Systems   
      
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