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|    Message 8,867 of 10,840    |
|    build to Smokey Joe    |
|    Re: checking for spaces    |
|    09 Oct 04 10:43:48    |
      From: build02DELTHIS@datafast.net.au              Smokey Joe wrote:              > Thank you to everyone.       >       > There is a language where you can say if x = spaces etc.       > To me that seems "clean".       >       > Smokey              G'day Smokey,       seems silly but ...       If x = " " then ...              For i = 1 to len(myString)        x = mid(myString,i,1)        If x = " " then        myString = Replace(myString, " ", "")        end if       next i              untested but you'll figure it out, I hope.       in VB select a keyword i.e. Replace then press F1.       cheers       build              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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