From: Chris@somewhere.in.uk   
      
   On Wed, 27 Apr 2005 10:35:31 +0200 Allcomp  wrote:   
      
   > *From:* Allcomp    
   > *Date:* Wed, 27 Apr 2005 10:35:31 +0200   
   >   
   > Hello,   
   >   
   > I have seen something really strange in VB6   
   >   
   > If I do a Int ( (5 * 1.2)) , I receive the value 5, but I should receive 6?   
   > Is this a bug or something really "normal".   
   > I can see that if I do   
   > ? int ((5 * 1.2  + 0.0000000000000003))   
   > I receive 6. If I add something smaller, I have 5 as a result   
   > What is strange is that If I do a ? 5*1.2, I receive 6 so (5 * 1.2)   
   > should do 6   
   > If I do Int ( (5 * 12 / 10)), the result is OK (6)   
   > What can I do to have it correct?   
   > Is there an option in VB6?   
   >   
   > Thank you   
   > Marc Allard   
   > Allcomp   
   >   
      
   Isn't this just typical of the inaccuracies often produced when using binary to   
   manipulate decimal numbers?   
      
   I suspect the actual result is probably something like 5.999999999 (etc) and   
   the   
   INT of that will be 5. Using Cint(5 * 1.2) will give the correct answer of 6 as   
   Cint round fractions whereas INT does not.   
      
   Chris.   
      
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