From: doppelherz@telia.com   
      
   Hi,   
      
   The fucntion you use (Int) does exactly what it is supposed to do. The   
   VB helpfile sais:   
      
   Int, Fix Functions   
   Returns the integer portion of a number.   
   Syntax   
   Int(number)   
      
   Int performs the "return integer" stuff on all bits and bobs of the   
   calculation not just the result, so int reads your calculation as   
   (5 * 1)   
      
   The way around it is to pass values, not calculations to the Int   
   function. You should have written   
      
   lngResult = (5 * 1.2)   
   Int(lngResult)   
      
   Regards DP   
      
      
      
   Allcomp wrote:   
   > Hello,   
   >   
   > I have seen something really strange in VB6   
   >   
   > If I do a Int ( (5 * 1.2)) , I receive the value 5, but I should receive 6?   
   > Is this a bug or something really "normal".   
   > I can see that if I do   
   > ? int ((5 * 1.2  + 0.0000000000000003))   
   > I receive 6. If I add something smaller, I have 5 as a result   
   > What is strange is that If I do a ? 5*1.2, I receive 6 so (5 * 1.2)   
   > should do 6   
   > If I do Int ( (5 * 12 / 10)), the result is OK (6)   
   > What can I do to have it correct?   
   > Is there an option in VB6?   
   >   
   > Thank you   
   > Marc Allard   
   > Allcomp   
      
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