Forums before death by AOL, social media and spammers... "We can't have nice things"
|    alt.engineering.electrical    |    Electrical engineering discussion forum    |    2,547 messages    |
[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]
|    Message 1,208 of 2,547    |
|    Don Kelly to pbx5619@gmail.com    |
|    Re: Aircon blower fan motor's speed ( vo    |
|    05 Jun 14 14:47:22    |
      From: dhky@shaw.ca              On 04/06/2014 1:16 PM, pbx5619@gmail.com wrote:       > My honda SM4's blower fan motor has a resistance of 0.8 Ω, & mostly used @       7½ v when alternator @ idle rpm produces 13½ v, i.e. 6v is wasted as heat by       these resistors which presumably have a total resistance of 6 ÷ 7½ x 0.8 Ω       = 0.64 Ω, i.e. #        of watts wasted must be 6v x 6v ÷ 0.64 Ω = 56¼ watt.       > In Dec'12 I noticed a Mercedes 350 has the same problem ( like cheaper cars       have ) of heat inside users' space when aircon is off, i.e. no buck converter       is used to reduce blower fan motor's voltage, so these resistors heat up this       space even after        aircon is switched off.       > Does any car maker use a buck converter to reduce this voltage ? Does any1       know where I can buy a buck converter with easily switchable output voltages       of 4, 6, 9 & 12 v, of ( 12 ÷ 0.8 Ω = ) 15 amp, to replace these wasteful       resistors ?       >       You are doing calculations on the basis of       V=(Re+Ri)I where Ri is 0.8 ohms and Re is 0.64 ohms- your calculations       are on the basis of a stalled motor-not one that is turning       Now consider that in fact you have       V=(Re +0.8)I +E where E is the back emf produced when the motor is       turning. (and much of the 7.5V measured is attributed to E), you will       find that the resistance added will be quite a bit larger than 0.64 ohms       (say 6 ohms)and the loss will be quite a bit lower-say in the 10 watt       range(without knowing the current, this is ball-parking estimates at       best). Yes, speed control with a resistor isn't the most efficient way       to do it but for motors of that size- but it is cheap-it isn't worth       spending more- the cost/benefit ratio for both the car maker and you       isn't worth it.       I suggest that, in addition to the voltage measurements-measure the       current. Then you can get a handle on the losses and the total input       power. While you are at it-check the panel lights and/or radio as heat       sources.              --       Don Kelly       remove the cross to reply              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]
(c) 1994, bbs@darkrealms.ca