From: dhky@shaw.ca   
      
   On 17/08/2013 7:33 AM, johnoshea19@gmail.com wrote:   
   > If the following equation gives the phase voltage for a PMAC when the phase   
   current (Iph) is in phase with the back emf (Eph)   
   >   
   > Vph = (Eph + Rs*Iph) + j*2*pi*frequency in hertz*Ls*Iph   
   >   
   > how would equation change when the Iph is 180 degrees out of phase with the   
   back emf?   
   >   
   replace Iph by -Iph or + by -   
      
      
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