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|    alt.anime    |    Japanese Anime and Hentai worship    |    1,634 messages    |
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|    Message 519 of 1,634    |
|    Raheman Velji to All    |
|    transportation revolution at hand (5/5)    |
|    10 Nov 04 18:52:29    |
      [continued from previous message]              kind of like how a comedian put it, "Why is it 'corn on the cob' and       'corn'? Instead, it should be 'corn' and 'corn off the cob'." Of       course, one could use the short-form "work" to indicate either       "general work", "effective work" or "productive work" by its use in       context.       ---------              -\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-       -|-|-| (4) ELECTRICITY |-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-       -/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-              Now, I am going to apply work using prescotts on an electrical       circuit.              ***************************       Let's find the average drift velocity:        -------------------------        A is the cross-section of the wire (m²)        n is "free" electrons per unit volume (electrons/m³)        e is the magnitude of charge of an electron        (1.602 * 10^(-19) C/electron)        v is the average drift velocity of the electrons (m/s)        I is the current in the wire (C/s)        dq is an infinitesimal amount of charge (C)        dt is an infinitesimal amount of time (s)        dN is an infinitesimal number of electrons (electrons)        -------------------------        (1) dq = e*dN               dN = nAv*dt        (2) dt = dN/(nAv)               (1)/(2) dq/dt = e*dN/(dN/nAv)        I = enAv        v = I/(enA)              ***************************       Let's find force:        -------------------------        W_j is the Work in Joules (N*m)        f is the force (N)        s is the distance (m)        V is the voltage (N*m/C)        -------------------------        W_j = F*s        dW_j = F*v*dt        dW_j/dt = F*v        V*I = F*v               V*I        F = -----        v               = VenA               -------------------------        P is pressure (Pa)        -------------------------        F        V = ---        enA               P        = --        en              So we can say that "voltage is the electromagnetic-pressure (created       by an EMF source) per density of charge."              Notice that the pressure supplied by an EMF has nothing to do with the       length of the circuit. A battery hooked to a 1-meter circuit of 1cm²       wire uses the same pressure to start a current as a similar battery       hooked to a 10000-meter circuit of similar wire!              ***************************        -------------------------        W_i is the Initial Work (in Prescotts) (N*s)        (the work done to start the electrical circuit)        t is a duration of time (s)        m_e is the mass of an electron (9.109 * 10^(-31) kg/electron)        -------------------------        W_i = F*t        = VenA*t              Notice that in this case "W_i" does not equal "m_e*v". This is       because over the period of time "t", which is greater than the average       change in time between electron collisions, the acceleration of the       electron is hindered when the electron loses its energy during a       collision.                     ***************************        -------------------------        U is Initial Work (in Prescotts) per Coulomb (N*s/C)        Q is an amount of charge (C)        p is the resistivity of the wire (ohm*m)        l is the length of the wire (m)        -------------------------        U = W_i/Q        = F/I        = (VenA)/(V/R)        = enAR        = enA*(p*l/A)        = enpl              Thus, we can say that "U" is a constant for any given circuit. So,       given any circuit, a constant amount of work is done to move a coulomb       along the circuit.                     ***************************        -------------------------        µ is Initial Work (in Prescotts) per Coulomb*meter (N*s/(C*m))        -------------------------        µ = dU/dl        = enp              So, the rate at which work is done per unit distance depends on the       material.              ***************************        -------------------------        t_c is the change in time between electron collisions (s)        -------------------------              Each electron gains "m_e*v" of energy before it makes a collision and       losses it's energy. The collision will take place in "t_c" seconds.       "U" is the amount of work to move a coulomb "l" meters along the wire.        And, in "l" meters, there will be "l/(v*t_c)" number of collisions.       So,               l m_e*v        ----- * ----- = U        v*t_c e               l*m_e        ------- = enpl        t_c*e               m_e        t_c = ----        e²np                     which is correct.              -\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-\-       -/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-/-              by Raheman Velji       November 7, 2004              you can also view this (and updated versions) at...       ...http://www.angelfire.com/un/rv              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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