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|    alt.comp.os.windows-xp    |    Actually wasn't too bad for a M$-OS    |    17,273 messages    |
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|    Message 17,142 of 17,273    |
|    EllisMorgan to R.Wieser    |
|    Re: Worldmap mercator projection - Latit    |
|    23 Jan 26 17:09:35    |
      XPost: alt.windows7.general, alt.comp.os.windows-10       From: ellis@ellis.invalid              On 21/01/2026 19:01, R.Wieser wrote:       > Paul,       >       >> ln(2.097283) = 0.740643 # Via the ln() button on my calculator       >       > And that 0.740643 points to somewhere between the northpole and canada on an       > ice plate. Where I'm quite sure Washington DC isn't located.       >       > Which was why I started to doubt that "ln()" equals "log()". But if not,       > what is it ?       >       >> The plot origin must not be where we think it is.       >       > Well, thats easy to check : Just calculate the result for a Latitude of Zero       > degrees. It should point at the equator.       >       >> Notice how in a lot of these mathematics discussions, nobody labels a damn       >> thing.       >       > Just mathematics ? A couple of weeks ago I tried to find example code for       > OpenSLL. I could find some, but with zero indication which version of the       > DLL it was for - and it matters a *lot*. It frustrates me to no end.       >       >>> 0.117959 is *way* to low       >>       >> But it is 0.5 minus that number, so 0.382 .       >       > In my previous message I mentioned that I multiply the result by half the       > height of the map, and subtract it from the equator (again, half the height       > of the map). That is the same, right ?       >       > Actually, it isn't. :-)       >       > Now you have shown that the log() in the formule you presented is exactly       > that (and not a elog() (natural log?) ) I had some solid ground from which I       > could look further.       >       > The whole problem is that your formule multiplies by the full height of the       > map, and my "simplified" one multiplied by *half* the maps height (and than       > subtracts from the equator).       >       > When I multiplied my result by two the result was the same as what came       > outof your formule.       >       > Thank you for that. :-)       >       > mea culpa : after noticing that my implementation of the formule didn't work       > I *should* have first tried to implement it as provided. :-|       >       >       > Than only one thing remains : Any idea why the first formule doesn't give       > the expected result ? |
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