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   alt.electronics      Electronics design, repair, worship, etc      7,706 messages   

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   Message 6,840 of 7,706   
   dxmm@albury.nospam.net.au to Uncle Peter   
   Re: Power factor, UPS, computer   
   05 Jan 14 22:01:21   
   
   From: Daniel47@teranews.com   
      
   On 04/01/14 00:21, Uncle Peter wrote:   
   > On Fri, 03 Jan 2014 12:52:45 -0000, Uncle Peter  wrote:   
   >   
   >> I was wondering why this 2nd hand UPS I bought says 1500VA, 980W.  Are   
   >> they assuming you don't have decent PFC on your computers?  When did   
   >> they start putting decent PFC in computers?   
   >>   
   >> I tested (with one of those plug in energy meters) a computer running   
   >> a good graphics card and CPU flat out with a cheap power supply (CIT)   
   >> with "passive power factor correction" (along with a stereo playing   
   >> loud and two old LCD screens), as this is where the UPS will be used.   
   >> The meter indicated a PF of 0.71.  I then tried a computer with a   
   >> Corsair power supply with "active power factor correction", running a   
   >> dual chip graphics card flat out, and got a PF of 0.98.   
   >   
   > This answer from Yahoo answers seems correct:   
   >   
   > "This is of the specification written by UPS manufacturers is widely   
   > misunderstood by users.   
   >   The actual load that can be supported can be up to 1500 VA OR 980W.   
   > These figures MUST NOT be exceeded. Power factor is irrelevant.   
   >   Thus with a PF of 0.98 the load can be 980W/1000VA (both figures are   
   > within the limits above, limited by W)   
   >   With a PF of 0.5 the load can be 1500VA/750W (limited by VA)   
   >   Battery standby time is determined by the W (watts) of the load. Thus   
   > if it will give 5 mins at 980W you can approximate that it will give 10   
   > mins at 490W."   
   >   
   > Presumably the invertor has a wattage limit and the transformer has a VA   
   > limit.   
      
   The transformer consists of two, inter-wound, inductors, one of which is   
   connected to a resistive-capacitive-inductive load. So the phase shift,   
   reflected back from the secondary winding into the primary winding will,   
   almost certainly, not be 1, i.e. purely resistive.   
      
   HTH   
      
   Daniel   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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