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|    Message 6,891 of 7,706    |
|    colonel_hack@yahoo.com to danwgrace@gmail.com    |
|    Re: Equation for LFO rate on Moog analog    |
|    29 Jun 14 23:10:37    |
      On Sun, 29 Jun 2014, danwgrace@gmail.com wrote:              > I have a Moog Voyager synth and it has an LFO with a rate setting. It       > is some sort of exponential scaling. On the front panel it goes from       > 0.2 to 50Hz, with 3Hz in the middle. These three values correspond with       > with the A to D values 0, 254 and 131 respectively on the LCD display.       > I was wondering if there is a likely equation that describes the circuit       > so I can approximate the rate (Hz) for each digital setting. I tried to       > fit an exponential curve and a quadratic curve to the values but neither       > worked out. Any ideas? In the meantime I may try a cubic spline.       >       Well, three points determine a quadratic so there isn't enough for a       cubic. The quadratic would be       .00142x^2-.16464x+.2       but       .2*16 = 3.2 ~=3       3*16=48 ~=50       so something like       .2*256^(x/256) =.2*2^(x/32)is suggested       for this       0->.2       131->3,414       254->49.03       and       127->3.13       maybe the 256s should be 255s or something but I'll bet       it's exponential and the marks are approximate. can you measue the LFO?       --record it AM modulating and look at the distance between peaks.              Ron              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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