From: lordyumyum@gmail.com   
      
   The statistical odds of getting exactly 5 zeros in an 8-digit number on a   
   dollar bill can be calculated using combinatorics.    
      
   The total number of ways to arrange 5 zeros and 3 non-zeros in an 8-digit   
   number is given by the binomial coefficient:   
      
   \[ \binom{8}{5} = \frac{8!}{5!(8-5)!} = 56 \]   
      
   The probability of any particular arrangement (assuming each arrangement is   
   equally likely) is \( \frac{1}{10^8} \) since there are 10 possible digits (0   
   through 9).   
      
   So, the probability of getting exactly 5 zeros in an 8-digit number is \( 56   
   \times \frac{1}{10^8} \)   
   Or   
   1 in 5 billion 600 million   
      
   Keep in mind that this assumes a uniform distribution of digits and that each   
   digit is equally likely to be any of the 10 possible digits. In reality, the   
   distribution of digits on a dollar bill may not be uniform due to serial   
   numbers, printing    
   processes, and other factors so could be a higher number than shown here.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)