Forums before death by AOL, social media and spammers... "We can't have nice things"
|    alt.magick    |    Meh.. another magic/spellcasting forum    |    90,437 messages    |
[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]
|    Message 89,060 of 90,437    |
|    Corey White to All    |
|    Blast from the past!    |
|    28 Dec 21 17:38:20    |
      From: realityhacker@gmail.com              I dug up this old article I wrote about kabbalah and maths. I actually had       a typo in one of the equations, so I figured better off share it again...              I have a theory that numbers are just variables, and that just maybe there       could be more than one answer for any problem. So then I thought about       Kabbalah. Each letter in the Jewish system of Gemantria, has a unique       number. So I decided to try this with the english words we use for       numbers. I wrote a program that solved it, and then learned online that       we only use 16 letters of the alphabet, which means you couldn't assign       every letter an integer in all possible numbers. But who needs to do       that? All we need are the numbers 0 - 10. Which can actually have       multiple values, but here is one:              To do this each letter is given one unique number. The numerical values       for all the letters in a word are added together. So o+n+e=1, and t+w+o=2.       That's all there is too it!              Here is a chart with the solution:.              [ E, F, G, H, I, L, N, O, R, S, T, U, V, W, X, Z]       [-2,-6, 0,-7, 7, 9, 2, 1, 4, 3,10, 5, 6,-9,-4,-3]              (zero) = (-3 + -2 + 4 + 1)              (one) = (1 + 2 + -2)              (two) = (10 + -9 + 1)              (three) = (10 + -7 + 4 + -2 + -2)              (four) = (-6 + 1 + 5 + 4)              (five) = (-6 + 7 + 6 + -2)              (six) = (3 + 7 + -4)              (seven) = (3 + -2 + 6 + -2 + 2)              (eight) = (-2 + 7 + 0 + -7 + 10)              (nine) = (2 + 7 + 2 + -2)              (ten) = (10 + -2 + 2)              Next to prove that we can actually use this system:              (ten^(two))*three = (10 + -2 + 2)^(10 + -9 + 1) * (10 + -7 + 4 + -2 + -2)                     (ten^(two))*three = ( 10^2 ) * 3              (ten^(two))*three = ( 100 ) * 3              (ten^(two))*three = 300              Finally:       We see if we can learn something new from this puzzle!              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
[   << oldest   |   < older   |   list   |   newer >   |   newest >>   ]
(c) 1994, bbs@darkrealms.ca