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   alt.magick      Meh.. another magic/spellcasting forum      90,437 messages   

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   Message 89,060 of 90,437   
   Corey White to All   
   Blast from the past!   
   28 Dec 21 17:38:20   
   
   From: realityhacker@gmail.com   
      
   I dug up this old article I wrote about kabbalah and maths.  I actually had   
   a typo in one of the equations, so I figured better off share it again...   
      
   I have a theory that numbers are just variables, and that just maybe there   
   could be more than one answer for any problem.  So then I thought about   
   Kabbalah.  Each letter in the Jewish system of Gemantria, has a unique   
   number.  So I decided to try this with the english words we use for   
   numbers.  I wrote a program that solved it, and then learned online that   
   we only use 16 letters of the alphabet, which means you couldn't assign   
   every letter an integer in all possible numbers.  But who needs to do   
   that?  All we need are the numbers 0 - 10.  Which can actually have   
   multiple values, but here is one:   
      
   To do this each letter is given one unique number. The numerical values   
   for all the letters in a word are added together. So o+n+e=1, and t+w+o=2.   
   That's all there is too it!   
      
   Here is a chart with the solution:.   
      
   [ E, F, G, H, I, L, N, O, R, S, T, U, V, W, X, Z]   
   [-2,-6, 0,-7, 7, 9, 2, 1, 4, 3,10, 5, 6,-9,-4,-3]   
      
   (zero) = (-3 + -2 + 4 + 1)   
      
   (one) = (1 + 2 + -2)   
      
   (two) = (10 + -9 + 1)   
      
   (three) = (10 + -7 + 4 + -2 + -2)   
      
   (four) = (-6 + 1 + 5 + 4)   
      
   (five) = (-6 + 7 + 6 + -2)   
      
   (six) = (3 + 7 + -4)   
      
   (seven) = (3 + -2 + 6 + -2 + 2)   
      
   (eight) = (-2 + 7 + 0 + -7 + 10)   
      
   (nine) = (2 + 7 + 2 + -2)   
      
   (ten) = (10 + -2 + 2)   
      
   Next to prove that we can actually use this system:   
      
   (ten^(two))*three = (10 + -2 + 2)^(10 + -9 + 1)  * (10 + -7 + 4 + -2 + -2)   
      
      
   (ten^(two))*three = ( 10^2 ) * 3   
      
   (ten^(two))*three = ( 100 ) * 3   
      
   (ten^(two))*three = 300   
      
   Finally:   
   We see if we can learn something new from this puzzle!   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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