From: address@is.invalid   
      
   Hello all,   
      
   I've got a batchfile in which I use the first (%1) argument as a switch to   
   decide which program should be started with the remaining arguments.   
      
   The problem is that I can't seem to find how to pass the unknown number   
   of(!) remaining arguments to the called program.   
      
   I'm aware of "%*", which stands for "all arguments but %0", but when I use   
   SHIFT (to get rid of "%1" it doesn't change.   
      
   iow:   
      
   echo %*   
   shift   
   echo %*   
      
   shows the same on both lines.   
      
   Question:   
   How do I provide all arguments starting from the second one to the program ?   
      
   Currently I just use "program.exe %2 %3 %4 %5 %6 %7 %8 %9" and be done with   
   it, but would like to know a way to provide more than 9 arguments to the   
   batchfile and still have it work.   
      
   Regards,   
   Rudy Wieser   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)