From: Zaidy036@air.isp.spam   
      
   On 4/22/2024 11:16 AM, R.Wieser wrote:   
   > Hello all,   
   >   
   > I've got a batchfile in which I use the first (%1) argument as a switch to   
   > decide which program should be started with the remaining arguments.   
   >   
   > The problem is that I can't seem to find how to pass the unknown number   
   > of(!) remaining arguments to the called program.   
   >   
   > I'm aware of "%*", which stands for "all arguments but %0", but when I use   
   > SHIFT (to get rid of "%1" it doesn't change.   
   >   
   > iow:   
   >   
   > echo %*   
   > shift   
   > echo %*   
   >   
   > shows the same on both lines.   
   >   
   > Question:   
   > How do I provide all arguments starting from the second one to the program ?   
   >   
   > Currently I just use "program.exe %2 %3 %4 %5 %6 %7 %8 %9" and be done with   
   > it, but would like to know a way to provide more than 9 arguments to the   
   > batchfile and still have it work.   
   >   
   > Regards,   
   > Rudy Wieser   
   >   
   >   
   Combine arguments separating by some known character and then split them   
   within the batch itself.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)