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|    alt.msdos.batch.nt    |    Fun with Windows NT batch files    |    68,980 messages    |
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|    Message 68,804 of 68,980    |
|    Herbert Kleebauer to Anton Shepelev    |
|    Re: Replacing a character with a percent    |
|    30 May 24 17:00:17    |
      From: klee@unibwm.de              On 30.05.2024 12:33, Anton Shepelev wrote:              >> and if VAR doesn't have any spaces or other delimiters und       >> there are only single #, than this should work (but what       >> is wrong with delayed expansion?):       >       > I consider this additional limitation as a challenge.              Batch programming is always a challenge.              >       >> set var=a#b#c       >>       >> set var2=%var:#= %&set var=&       >> for %%i in (%var2%) do call set var=%%var%%%%i%%%%       >> set var=%var:~0,-1%       >>       >> echo %var%                     > The `&' in `set var=&' seems       > unnecessary. Is it there to avoid potential trailing       > whitespace?              Yes.              But why do you want to do it without delayed expansion?       You don't have to use it for the complete batch code,       just for the replacement of the #:              set var=a#b##c              setlocal enabledelayedexpansion&set p=%%&set var=%var:#=!p!%       endlocal&set var=%var%              echo %var%              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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