From: klee@unibwm.de   
      
   On 27.11.2024 17:21, Anton Shepelev wrote:   
   > Hello, all.   
   >   
   > What does the following script:   
   >   
   > @ECHO OFF   
   > FOR /F "tokens=2,* delims= " %%A in ("%*") DO SET ARGS=%%B   
   > ECHO M:1:%1   
   > ECHO M:2:%2   
   > ECHO M:*:%ARGS%   
   >   
   > stored as test.bat invoked as   
   >   
   >> test.bat a "b,c" d e   
   >   
   > print:   
   >   
   > 1:a   
   > 2:"b,c"   
   > *:c" d e   
   >   
   > ?   
      
   Remove the @ECHO OFF then you can see the executed command:   
      
   FOR /F "tokens=2,* delims= " %A in ("a "b c" d e") DO SET ARGS=%B   
      
   FOR /F ["options"] %variable IN ("string") DO command [command-parameters]   
      
   Because the , is replaced by a space (why?), string becomes: a "b c" d e   
   Token 1:a   
   Token 2:"b   
          *:c" d e   
      
      
      
      
   > I expected it to print:   
   >   
   > 1:a   
   > 2:"b,c"   
   > *:d e   
      
   You get this if you use:   
      
   FOR /F "tokens=2,* delims= " %%A in ('echo %*') DO SET ARGS=%%B   
      
   > because the FOR /F loop should split the parameter by the   
   > space characer, and end up with all the token after the second   
   > one in the ARGS variable. Why is the comma treated as a command   
   > separator at some point?   
   >   
      
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