From: muta...@gmail.com   
      
   On Tuesday, July 13, 2021 at 3:16:03 PM UTC+10, wolfgang kern wrote:   
      
   > > No. On a real 8086. The x'66' will be ignored. So a real   
   > > 8086 and PM32 will both work, right?   
      
   > Not sure why you want a 16 bit operand in PM32.   
      
   I'm trying to do 16-bit programming with a bigger   
   EFFECTIVE shift than 4 bits.   
      
   > the 66 "may"   
   > be ignored by 8086/88, could be an alias for other as well.   
      
   How can it be an alias on an 8086?   
      
   > If you want to always use 16 bit code then use PM16.   
      
   You know what? That's a great idea! I didn't think of the   
   murky PM16 world.   
      
   > only but all segment registers are different in PM16.   
      
   They are selectors. But I can make them look like   
   segment registers with a particular shift.   
      
   > AND with PM16 you can use 64KB blocks anywhere within 4GB.   
      
   I assume I still have 16384 selectors, so I will still be limited   
   to a total of 1 GiB.   
      
   BFN. Paul.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)