From: joemonk64@gmail.com   
      
   > Crikey. Talk about a misunderstanding.   
   >   
   Well as we already know 0x5333 shifted left 5 bits is 0x0A6660   
      
   0x0A6660 + 0x0A71 = 0x0A70D1   
      
   But you still missed the point.   
      
   With 4 bit shifts...   
      
   0x5555 + 0x0005 = 0x55555   
   0x5333 + 0x2225 = 0x55555   
      
   So, mutliple segment:offset pairs point to the same physical address.   
      
   But if I take those same segment:offset pairs and apply 5 bit shifts to them,   
   it breaks segmentation. Thus, none of the existing code base will work.   
      
   Joe   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)