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|    Message 3,424 of 4,255    |
|    mutazilah@gmail.com to Joe Monk    |
|    Re: segmentation    |
|    10 Nov 22 14:18:17    |
      From: muta...@gmail.com              On Friday, November 11, 2022 at 12:33:44 AM UTC+8, Joe Monk wrote:       > > You need to actually do something with memory. I need to know if you       > > are doing ANY instructions that use the full 64 bits of a register to       > > address memory. If you are, it is a 64-bit program.       > So, by that definition, every z/Arch program is 64-bit, regardless of AMODE.       >       > All z/Arch physical memory accesses are 64-bit.              No, that's not correct. If a program only ever populates the low       32 bits of registers, to use as addresses, then it is a 32-bit       program.              Just because someone moves a properly-written 32-bit program (that       doesn't rely on address masking) from S/370 to z/Arch, doesn't       magically turn it into a 64-bit program. Life would be so simple if       it did. The bitness is decided at build time. ie how many address bits       are populated, and whether the programmer is a jackass who relied       on masking.              BFN. Paul.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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