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|    alt.os.linux    |    Getting to be as bloated as Windows!    |    107,822 messages    |
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|    Message 107,560 of 107,822    |
|    Dan Purgert to All    |
|    Re: How do "they" Speed-test Internet Li    |
|    10 Sep 25 10:52:03    |
      XPost: alt.comp.os.windows-11       From: dan@djph.net              On 2025-09-10, Daniel70 wrote:       > On 10/09/2025 2:30 am, Carlos E.R. wrote:       >> On 2025-09-09 16:04, Daniel70 wrote:       >>> On 9/09/2025 10:41 pm, Carlos E.R. wrote:       >>>> On 2025-09-09 14:34, Daniel70 wrote:       >>>>> On 9/09/2025 10:13 pm, Dan Purgert wrote:       >>>>>> On 2025-09-09, Daniel70 wrote:       >>>>       >>>>>>> YEAP!! Undergerstumble!! But did my data travel via Undersea       >>>>>>> Co-ax or via Low Earth orbit Satellite or via High Earth orbit       >>>>>>> Satellite ..... or via one of those reflector Panels       >>>>>>> (supposedly) left on The Moon by the Apollo Astronauts??       >>>>>>       >>>>>> It doesn't matter - throughput is not latency.       >>>>>       >>>>> But I'm not really interested in throughput OR latency but how long       >>>>> it takes to get from A (my place) to B (test site) .... and then       >>>>> how long it takes to get from B (test site) to A (my place).       >>>>       >>>> That's latency.       >>>>       >>> Ah!! O.K., my mistake.       >>>       >>> I thought 'Latency' was how long it took something to get up'n'going!!       >>> i.e. overcoming "inertia".       >>       >> I asked chatgpt to make sure. :-)       >>       >> Q: In the scenario of measuring internet connection speed, what would be       >> the latency?       >>       >> A: In the context of measuring **internet connection speed**,       >> **latency** refers to the **time it takes for a data packet to travel       >> from your device to a remote server and back**. It's usually measured in       >> **milliseconds (ms)** and is also known as **ping**.       >       > So a "one-way" journey.              No, "There and back again".              For example, a 22.1 millisecond ping to google.com means that               1. We send an ICMP Echo request to Google at time = 0        2. Google got it at time = x (we will assume x=11, knowing "22.1"        was the full RTT)        3. Google created an ICMP Reply at time = x+y (we will assume y=0.1,        and add that to "x=11" from step 2)        4. We get the Reply at 22.1 milliseconds              Or, if we're doing "human scale" time.              I ask Voyager 1 for some data at time = 0       The spacecraft receives the message some 20-24 hours later.       The spacecraft "instantly" responds       I receive the message 20-24 hours later.              Total latency (Round-Trip Time) of my request -- 40 to 48 hours.              >       >> ### Breakdown:       >>       >> * **Latency = Round-trip time (RTT)**       >       > But wait, "Latency" is now Return Trip Time!!              No, not "Return", "Round" Trip (aka "There and Back Again").              >>       >> * **100 Mbps** is how much data can be received per second.       >       > ... but one-way, only!!              Link data rate and RTT are not exactly "coupled" to one another.              You can have a very high-capacity (data / payload) link that has high       latency -- for example, a station wagon full of tapes hurtling down the       freeway.              You can have a very low-capacity (data / payload) link that has low       latency -- for example a 56k modem that is 22 milliseconds away from       google.                     >       >> * **20 ms** latency means it takes 20 milliseconds to send a small       >> request to the server and get a reply.       >       > So is that "Round Trip" time??              yes.              --       |_|O|_|       |_|_|O| Github: https://github.com/dpurgert       |O|O|O| PGP: DDAB 23FB 19FA 7D85 1CC1 E067 6D65 70E5 4CE7 2860              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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