XPost: alt.algebra.help   
   From: recneps.w.divad@elcaro.moc   
      
   mathedman wrote:   
      
   > On Wed, 14 Jul 2004 15:03:14 +0100, Dave    
   > wrote:   
   >   
   >   
   >>   
   >>Harlan Osier wrote:   
   >>   
   >>>Is this correct???   
   >>   
   >>Yes, in base sqrt(26).   
   >   
   >   
   >   
   >  Uhh-hhh     what are the digits in base SQRT(26) ??   
      
   Oops, yes, you're right - 5*5 would be 55, not 99, assuming that 5   
   exists in this base and is equal to 5 base 10.  I was thinking 1 less   
   than 100.   
      
   Ok, how about in C++ overloading class foo's operator * to return   
   integer 99 regardless of parameters, and a foo(int) constructor, then   
   foo(5)*foo(5) would be 99.   
      
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