From: NOSPAM_b.postlethwaite@strath.ac.uk   
      
   The process you've got is an overdamped, second-order process and by   
   multiplying it by 1/s you are inserting a unit step change into the input.   
   The response you get should have an approximate 's' shape with a final value   
   (as t tends to infinity) of 0.00375 (0.00375 is the steady-state gain times   
   the change in the input, which is 1).   
      
      
      
   The equation you've got from Maple will settle on 0.1 (the U shouldn't be   
   there), and so it doesn't look right. I suspect the exponential parts are   
   incorrect too. Get yourself a control textbook - they're stuffed full of   
   standard solutions to step changes!   
      
      
      
   Regards,   
      
      
      
   Bruce Postlethwaite   
      
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