From: NOSPAM_b.postlethwaite@strath.ac.uk   
      
   Whoops - I boobed, I didn't look at the terms in the denominator.   
      
   The steady-state gain is 0.00375/(.15*.25) = 0.1   
      
   If you put a unit step into this transfer function it will settle at 0.1 -   
   are you sure the 0.00375 term shouldn't be 0.0375?   
      
   Sorry!   
      
   "Bruce Postlethwaite"  wrote in message   
   news:e2i1d5$m75$1@dennis.cc.strath.ac.uk...   
   >   
   >   
   > The process you've got is an overdamped, second-order process and by   
   > multiplying it by 1/s you are inserting a unit step change into the input.   
   > The response you get should have an approximate 's' shape with a final   
   > value (as t tends to infinity) of 0.00375 (0.00375 is the steady-state   
   > gain times the change in the input, which is 1).   
   >   
   >   
   >   
   > The equation you've got from Maple will settle on 0.1 (the U shouldn't be   
   > there), and so it doesn't look right. I suspect the exponential parts are   
   > incorrect too. Get yourself a control textbook - they're stuffed full of   
   > standard solutions to step changes!   
   >   
   >   
   >   
   > Regards,   
   >   
   >   
   >   
   > Bruce Postlethwaite   
   >   
   >   
      
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