XPost: comp.theory, sci.logic   
   From: polcott333@gmail.com   
      
   On 7/26/2025 2:52 PM, Mr Flibble wrote:   
   > On Sat, 26 Jul 2025 14:26:27 -0500, olcott wrote:   
   >   
   >> On 7/26/2025 1:30 PM, Alan Mackenzie wrote:   
   >>> In comp.theory olcott wrote:   
   >>>   
   >>>> The error of all of the halting problem proofs is that they require a   
   >>>> Turing machine halt decider to report on the behavior of a directly   
   >>>> executed Turing machine.   
   >>>   
   >>>> It is common knowledge that no Turing machine decider can take another   
   >>>> directly executing Turing machine as an input, thus the above   
   >>>> requirement is not precisely correct.   
   >>>   
   >>>> When we correct the error of this incorrect requirement it becomes a   
   >>>> Turing machine decider indirectly reports on the behavior of a   
   >>>> directly executing Turing machine through the proxy of a finite string   
   >>>> description of this machine.   
   >>>   
   >>>> Now I have proven and corrected the error of all of the halting   
   >>>> problem proofs.   
   >>>   
   >>> No you haven't, the subject matter is too far beyond your intellectual   
   >>> capacity.   
   >>>   
   >>>   
   >> It only seems to you that I lack understanding because you are so sure   
   >> that I must be wrong that you make sure to totally ignore the subtle   
   >> nuances of meaning that proves I am correct.   
   >>   
   >> No Turing machine based (at least partial) halt decider can possibly   
   >> *directly* report on the behavior of any directly executing Turing   
   >> machine. The best that any of them can possibly do is indirectly report   
   >> on this behavior through the proxy of a finite string machine   
   >> description.   
   >   
   > Partial decidability is not a hard problem.   
   >   
   > /Flibble   
      
   My point is that all of the halting problem proofs   
   are wrong when they require a Turing machine decider   
   H to report on the behavior of machine M on input i   
   because machine M is not in the domain of any Turing   
   machine decider. Only finite strings such as ⟨M⟩ the   
   Turing machine description of machine M are its   
   domain.   
      
   --   
   Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius   
   hits a target no one else can see." Arthur Schopenhauer   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   
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