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   comp.ai.philosophy      Perhaps we should ask SkyNet about this      59,235 messages   

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   Message 57,749 of 59,235   
   olcott to joes   
   Re: Who is telling the truth here? HHH(D   
   01 Aug 25 09:46:22   
   
   XPost: comp.theory, sci.logic   
   From: polcott333@gmail.com   
      
   On 8/1/2025 1:53 AM, joes wrote:   
   > Am Thu, 31 Jul 2025 19:18:36 -0500 schrieb olcott:   
   >> On 7/31/2025 7:07 PM, Richard Damon wrote:   
   >>> On 7/31/25 11:50 AM, olcott wrote:   
   >   
   >>>> On 7/29/2025 11:22 PM, Alan Mackenzie wrote:   
   >>>>   > It is a lack of technical ability on your part which is unable to   
   >>>>   > judge whether such a correct simulation is possible.  Everybody   
   >>>>   > else sees that it is not, so further questions about it are   
   >>>>   > non-sensical.   
   >>>> HHH emulates DDD in a separate process context. When this DDD calls   
   >>>> HHH(DDD) the original HHH emulates this HHH in the DDD process   
   >>>> context.   
   >>> And that separate proccess, if left unaborted, would halt. But HHH   
   >>> gives up and aborts it, so the process is Halting, not non-halting.   
      
   > And HHH cannot simulate itself to its undeniable halting state.   
   >   
   >>>> This emulated HHH creates yet another process context to emulate its   
   >>>> own DDD. When this DDD calls yet another HHH(DDD) this provides enough   
   >>>> execution trace that the repeating pattern can be seen.   
   >>> But the pattern isn't non-halting by the fact that DDD is shown to be   
   >>> halting.   
   >> *No not at all. Not in the least little bit* Recursive simulation is   
   >> only a little more difficult than self recursion.   
      
   > DDD halts if it weren't aborted.   
   >   
      
   (1) That is counter-factual. Neither HHH() nor DDD() nor DDD   
   simulated by HHH ever stops running unless HHH(DDD) aborts   
   its input.   
      
   (2) I have never been taking about DDD() the behavior of a non-input.   
   Turing machines are only accountable for the behavior that their   
   inputs specify, they are never accountable for any non-inputs.   
      
   (3) When I make a claim about DDD simulated by HHH and this is   
   changed to the behavior of the directly executed DDD this is   
   a dishonest tactic known as the strawman error.   
      
   void DDD()   
   {   
      HHH(DDD);   
      return;   
   }   
      
   Executed HHH simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   that simulates DDD that calls HHH(DDD)   
   Then HHH kills the whole simulation process and returns 0   
      
   >> When N instructions of DDD are correctly emulated by every HHH that can   
   >> possibly exist (technically this is an infinite set of HHH/DDD pairs)   
   >> no emulated DDD can possibly halt and every directly executed DDD()   
   >> halts.   
      
   > See, and I thought DDD was a concrete program filled in with HHH,   
   > which aborts after two levels of simulation, not something that   
   > calls "HHH" symbolically, producing many different programs.   
   >   
      
   I had to turn it into an infinite set of HHH/DDD   
   pairs so that it could be more easily understood   
   that DDD simulated by HHH cannot possibly halt.   
      
   When HHH detects the above non-halting behavior   
   pattern it kills the whole simulation process so   
   there is no stack unwinding.   
      
   --   
   Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius   
   hits a target no one else can see." Arthur Schopenhauer   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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