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|    comp.ai.philosophy    |    Perhaps we should ask SkyNet about this    |    59,235 messages    |
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|    Message 57,827 of 59,235    |
|    olcott to Richard Damon    |
|    Re: Who is telling the truth here? HHH(D    |
|    04 Aug 25 20:31:55    |
   
   XPost: comp.theory, sci.logic   
   From: polcott333@gmail.com   
      
   On 8/4/2025 8:25 PM, Richard Damon wrote:   
   > On 8/4/25 9:42 AM, olcott wrote:   
   >> On 8/4/2025 7:47 AM, Fred. Zwarts wrote:   
   >>> Op 02.aug.2025 om 16:16 schreef olcott:   
   >>>> On 8/2/2025 4:18 AM, Fred. Zwarts wrote:   
   >>>>> Op 01.aug.2025 om 16:46 schreef olcott:   
   >>>>>> On 8/1/2025 1:53 AM, joes wrote:   
   >>>>>>> Am Thu, 31 Jul 2025 19:18:36 -0500 schrieb olcott:   
   >>>>>>>> On 7/31/2025 7:07 PM, Richard Damon wrote:   
   >>>>>>>>> On 7/31/25 11:50 AM, olcott wrote:   
   >>>>>>>   
   >>>>>>>>>> On 7/29/2025 11:22 PM, Alan Mackenzie wrote:   
   >>>>>>>>>> > It is a lack of technical ability on your part which is   
   >>>>>>>>>> unable to   
   >>>>>>>>>> > judge whether such a correct simulation is possible.   
   >>>>>>>>>> Everybody   
   >>>>>>>>>> > else sees that it is not, so further questions about it are   
   >>>>>>>>>> > non-sensical.   
   >>>>>>>>>> HHH emulates DDD in a separate process context. When this DDD   
   >>>>>>>>>> calls   
   >>>>>>>>>> HHH(DDD) the original HHH emulates this HHH in the DDD process   
   >>>>>>>>>> context.   
   >>>>>>>>> And that separate proccess, if left unaborted, would halt. But HHH   
   >>>>>>>>> gives up and aborts it, so the process is Halting, not non-   
   >>>>>>>>> halting.   
   >>>>>>   
   >>>>>>> And HHH cannot simulate itself to its undeniable halting state.   
   >>>>>>>   
   >>>>>>>>>> This emulated HHH creates yet another process context to   
   >>>>>>>>>> emulate its   
   >>>>>>>>>> own DDD. When this DDD calls yet another HHH(DDD) this   
   >>>>>>>>>> provides enough   
   >>>>>>>>>> execution trace that the repeating pattern can be seen.   
   >>>>>>>>> But the pattern isn't non-halting by the fact that DDD is shown   
   >>>>>>>>> to be   
   >>>>>>>>> halting.   
   >>>>>>>> *No not at all. Not in the least little bit* Recursive   
   >>>>>>>> simulation is   
   >>>>>>>> only a little more difficult than self recursion.   
   >>>>>>   
   >>>>>>> DDD halts if it weren't aborted.   
   >>>>>>>   
   >>>>>>   
   >>>>>> (1) That is counter-factual. Neither HHH() nor DDD() nor DDD   
   >>>>>> simulated by HHH ever stops running unless HHH(DDD) aborts   
   >>>>>> its input.   
   >>>>>   
   >>>>>   
   >>>>> It is irrelevant what a hypothetical non-input would do. HHH   
   >>>>> aborts, so DDD and HHH, both the directly executing and the   
   >>>>> simulated versions halt.   
   >>>>>   
   >>>>   
   >>>> DDD correctly simulated by HHH cannot possibly reach   
   >>>> its own simulated "return" instruction final halt state   
   >>>> in 1 to infinity steps of correct simulation. When the   
   >>>> simulation is aborted the entire process is killed so   
   >>>> there is no stack unwinding.   
   >>>>   
   >>>>>>   
   >>>>>> (2) I have never been taking about DDD() the behavior of a non-input.   
   >>>>>> Turing machines are only accountable for the behavior that their   
   >>>>>> inputs specify, they are never accountable for any non-inputs.   
   >>>>>   
   >>>>>   
   >>>>> And this input specifies a program with code to abort, so it   
   >>>>> specifies a halting program. When HHH does not see that, it fails.   
   >>>>>   
   >>>>   
   >>>> I discovered a case where the correct simulation   
   >>>> and the direct execution have different halting   
   >>>> behaviors.   
   >>>   
   >>> No, you dreamed, but could not prove it. Only by twisting the meaning   
   >>> of the words, you could make yourself believing it.   
   >>>   
   >>>>   
   >>>>>>   
   >>>>>> (3) When I make a claim about DDD simulated by HHH and this is   
   >>>>>> changed to the behavior of the directly executed DDD this is   
   >>>>>> a dishonest tactic known as the strawman error.   
   >>>>>   
   >>>>> When the input specifies a halting behaviour, it is an error to   
   >>>>> close your eyes and pretend that it does not exist.   
   >>>>>   
   >>>>>>   
   >>>>>> void DDD()   
   >>>>>> {   
   >>>>>> HHH(DDD);   
   >>>>>> return;   
   >>>>>> }   
   >>>>>>   
   >>>>>> Executed HHH simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> that simulates DDD that calls HHH(DDD)   
   >>>>>> Then HHH kills the whole simulation process and returns 0   
   >>>>>   
   >>>>> Counterfactual. HHH abors after a few cycles, when only one more   
   >>>>> cycle is needed to complete the simulation, as proven by simulators   
   >>>>> that do not abort the exact same input.   
   >>>>>   
   >>>>   
   >>>> The above HHH aborts after ten recursive simulations   
   >>>> because people here did not understand that there were   
   >>>> any recursive simulation when I only show one or two.   
   >>>   
   >>> That does not make any difference. We also see that you are cheating,   
   >>> by not only changing the simulator, but also the simulated input.   
   >>> World class simulators show that the original input, when correctly   
   >>> simulated, reaches its final halt state after tree recursion.   
   >>> The HHH that simulates 10 recursions would also reach the final halt   
   >>> state for this same input.   
   >>> But, because your are cheating, you changed the input, which now   
   >>> needs eleven recursion to halt.   
   >>> We see in this way, the, no matter how many recursions you simulate,   
   >>> this method is unable to reach the final halt state that is specified   
   >>> in the input when we construct a new DDD with this new HHH.   
   >>>   
   >>>>   
   >>>>>>   
   >>>>>>>> When N instructions of DDD are correctly emulated by every HHH   
   >>>>>>>> that can   
   >>>>>>>> possibly exist (technically this is an infinite set of HHH/DDD   
   >>>>>>>> pairs)   
   >>>>>>>> no emulated DDD can possibly halt and every directly executed DDD()   
   >>>>>>>> halts.   
   >>>>>>   
   >>>>>>> See, and I thought DDD was a concrete program filled in with HHH,   
   >>>>>>> which aborts after two levels of simulation, not something that   
   >>>>>>> calls "HHH" symbolically, producing many different programs.   
   >>>>>>>   
   >>>>>>   
   >>>>>> I had to turn it into an infinite set of HHH/DDD   
   >>>>>> pairs so that it could be more easily understood   
   >>>>>> that DDD simulated by HHH cannot possibly halt.   
   >>>>>>   
   >>>>>> When HHH detects the above non-halting behavior   
   >>>>>> pattern it kills the whole simulation process so   
   >>>>>> there is no stack unwinding.   
   >>>>>>   
   >>>>> There is no non-halting behaviour pattern, only a finite number   
   >>>>> more than N instructions are needed to reach the final input *for   
   >>>>> this input*.   
   >>>>   
   >>>> counter-factual   
   >>>>   
   >>>> _DDD()   
   >>>> [00002192] 55 push ebp   
   >>>> [00002193] 8bec mov ebp,esp   
   >>>> [00002195] 6892210000 push 00002192 // push DDD   
   >>>> [0000219a] e833f4ffff call 000015d2 // call HHH   
   >>>> [0000219f] 83c404 add esp,+04   
      
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   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   
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