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|    comp.ai.philosophy    |    Perhaps we should ask SkyNet about this    |    59,235 messages    |
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|    Message 57,855 of 59,235    |
|    Fred. Zwarts to All    |
|    Re: Who is telling the truth here? HHH(D    |
|    07 Aug 25 11:14:30    |
      XPost: comp.theory, sci.logic       From: F.Zwarts@HetNet.nl              Op 07.aug.2025 om 05:24 schreef olcott:       > On 8/6/2025 9:27 PM, Richard Damon wrote:       >> On 8/6/25 7:53 AM, olcott wrote:       >>> On 8/6/2025 5:54 AM, Richard Damon wrote:       >>>> On 8/5/25 11:47 PM, olcott wrote:       >>>>>       >>>>> It corrects the error of the requirement that       >>>>> a halt decider reports on its own behavior.       >>>>       >>>> But it isn't an error.       >>>>       >>>> Halt Deciders need to answer about *ANY* program, and they are       >>>> programs.       >>>>       >>>>>       >>>>> "The contradiction in Linz's (or Turing's) self-referential       >>>>> halting construction only appears if one insists that the       >>>>> machine can and must decide on its own behavior, which is       >>>>> neither possible nor required."       >>>>>       >>>>> https://chatgpt.com/share/6890ee5a-52bc-8011-852e-3d9f97bcfbd8       >>>>>       >>>>       >>>> Because you lied to it and said it was an error.       >>>>       >>>       >>> The above paragraph is proved true by the meaning of its words.       >>> When we ask a Turing machine to report on its own behavior we       >>> are assuming that its Turing Machine description is an accurate       >>> proxy for this behavior. When there are exceptions to this rule       >>> then we cannot possibly ask a Turing machine about its own behavior.       >>> This is easily corrected:       >>       >> But the existance of UTMs means that it IS possible to make a perfect       >> proxy, as the UTM can completely recreate the behavior of ANY machine       >> from its Turing Machine Description.       >>       >> All you are doing is admitting that you think errors and lies are ok.       >>       >       > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.UTM ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qy,       > Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.UTM ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn       >       > After a finite number of correct simulations the UTM       > will reach its final state yet no simulated UTM ever       > reaches its own final state.       >              Indeed, that is the proof that such a simulation fails.       No simulator exists that is able to simulate correctly all halting       programs up to the end,because it fails to simulate correctly code that       resembles its own code.              --- SoupGate-Win32 v1.05        * Origin: you cannot sedate... all the things you hate (1:229/2)    |
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