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   comp.ai.philosophy      Perhaps we should ask SkyNet about this      59,235 messages   

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   Message 58,156 of 59,235   
   olcott to Kaz Kylheku   
   Re: "there will still be a nested simula   
   23 Oct 25 19:00:31   
   
   XPost: comp.theory, sci.logic, sci.math   
   From: polcott333@gmail.com   
      
   On 10/23/2025 6:55 PM, Kaz Kylheku wrote:   
   > On 2025-10-23, olcott  wrote:   
   >> On 10/23/2025 5:40 PM, dbush wrote:   
   >>> On 10/23/2025 6:08 PM, olcott wrote:   
   >>>> On 10/22/2025 6:01 PM, Kaz Kylheku wrote:   
   >>>>> On 2025-10-22, olcott  wrote:   
   >>>>>> On 10/22/2025 3:20 PM, Kaz Kylheku wrote:   
   >>>>>>> On 2025-10-22, olcott  wrote:   
   >>>>>>>> On 10/22/2025 2:52 PM, Kaz Kylheku wrote:   
   >>>>>>>>> On 2025-10-22, André G  Isaak  wrote:   
   >>>>>>>>>> On 2025-10-22 12:40, Kaz Kylheku wrote:   
   >>>>>>>>>>> But that entire bundle is one fixed case DD, with a single   
   >>>>>>>>>>> behavior,   
   >>>>>>>>>>> which is a property of DD, which is a finite string.   
   >>>>>>>>>>   
   >>>>>>>>>> I think part of the problem here is that Olcott doesn't grasp   
   >>>>>>>>>> that the   
   >>>>>>>>>> "finite string input" DD *must* include as a substring the entire   
   >>>>>>>>>> description of HHH.   
   >>>>>>>>>   
   >>>>>>>>> Furthermore, he doesn't get that it doesn't literally have to be   
   >>>>>>>>> HHH,   
   >>>>>>>>> but the same algorithm: a workalike.   
   >>>>>>>>>   
   >>>>>>>>> The HHH analyzing DD's halting could be in C, while the HHH   
   >>>>>>>>> called by DD could be in Python.   
   >>>>>>>>   
   >>>>>>>> DD does call HHH(DD) in recursive simulation   
   >>>>>>>> and you try to get away with lying about it.   
   >>>>>>>   
   >>>>>>> I'm saying that's not a requirement in the halting problem.   
   >>>>>>>   
   >>>>>>> DD does not have to use that implementation of HHH; it can have   
   >>>>>>> its own clean-room implementation and it can be in any language.   
   >>>>>>>   
   >>>>>>> But nonetheless, yes, there will still be a nested simulation tower.   
   >>>>>>>   
   >>>>>>   
   >>>>>> I made sure to read what you said all the way through   
   >>>>>> this time. DD correctly simulated by HHH cannot possibly   
   >>>>>> reach its own final halt state no matter what HHH does.   
   >>>>>   
   >>>>> The /simulation/ of DD by HHH will not /reproduce/ the halt   
   >>>>> state of DD, which DD undeniably /has/.   
   >>>>>   
   >>>>   
   >>>> The finite string as an actual input to HHH(DD)   
   >>>   
   >>> i.e. finite string DD which is the description of machine DD and   
   >>> therefore is stipulated to specify all semantic properties of the   
   >>> described machine, including halting when executed directly.   
   >>>   
   >>>> *does not have the halting property*   
   >>>   
   >>> False, see above.>   
   >>>> Turing machine deciders only compute the mapping   
   >>>> from their finite string inputs   
   >>>   
   >>> And the finite string input DD has the halting property as show above.   
   >>>   
   >>>>   
   >>>> Turing machine deciders only compute the mapping   
   >>>> from their finite string inputs   
   >>>>   
   >>>> Turing machine deciders only compute the mapping   
   >>>> from their finite string inputs   
   >>>>   
   >>>> The DD that has the halting property   
   >>>   
   >>> i.e. finite string DD which is an input to HH   
   >>>   
   >>>> is not an input   
   >>> False, see above.   
   >>   
   >> Correct simulation is defined as simulation   
   >> according to the semantics of the specification   
   >> language: C, x86 or TM description.   
   >   
   > Correct simulation must continue while the   
   > final instruction has not been reached.   
   >   
   > The correct simulation of a non-terminating machine   
   > never stops.   
   >   
   > The correct simulation of a terminating machine   
   > must reach its halt state.   
   >   
   >> The execution trace of DD correctly simulated   
   >> by HHH differs from the execution trace of   
   >> DD correctly simulated HHH1 proving that I   
   >> am right and you are stupid or dishonest.   
   >   
   > Someone idenfiable as an engineer, and not necessarily even   
   > a great one, will immediately know that if two simulations   
   > (of a deterministic program that has a single behavior)   
   > do not agree, /at most/ one of them can be called "correct".   
   >   
      
   Until that bother to actually pay complete attention   
   then they will suddenly realize that the behavior of   
   DD correctly simulated by HHH specifies non-terminating   
   recursive simulation that cannot possibly reach its   
   own simulated final halt state.   
      
   This is why I have to tell ChatGPT: do not assume   
   one damn thing work through all the actual steps   
   and see what you find.   
      
   > They could be both wrong, but they cannot be both right.   
   >   
   > If you think so, then obviously you must be stupid   
   > or dishonest.   
   >   
      
      
   --   
   Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius   
   hits a target no one else can see." Arthur Schopenhauer   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   

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