XPost: comp.theory, comp.lang.c++, comp.lang.c   
   From: dbush.mobile@gmail.com   
      
   On 10/26/2025 9:56 PM, olcott wrote:   
   > On 10/26/2025 8:49 PM, dbush wrote:   
   >>   
   >> You mean   
   > *dbush is now dishonored in his deceit*   
   >   
      
   There's no deceit in the fact that you admitted on the record that the   
   input to HHH(DD) specifies a halting computation:   
      
      
   On 10/26/2025 9:38 PM, dbush wrote:   
    > On 10/26/2025 9:32 PM, olcott wrote:   
    >> On 10/26/2025 8:28 PM, dbush wrote:   
    >>> On 10/26/2025 9:20 PM, olcott wrote:   
    >>>> On 10/26/2025 8:16 PM, Kaz Kylheku wrote:   
    >>>>   
    >>>> int DD()   
    >>>> {   
    >>>>    int Halt_Status = HHH(DD);   
    >>>>    if (Halt_Status)   
    >>>>      HERE: goto HERE;   
    >>>>    return Halt_Status;   
    >>>> }   
    >>>>   
    >>>> HHH(DD) simulates DD that calls HHH(DD) to do this   
    >>>> again and again until HHH figures out what is up.   
    >>>>   
    >>>>   
    >>>   
    >>> And HHH figures it out incorrectly as proven by the code posted by   
   Katz.   
    >>>   
    >>   
    >> You can't even get his name correctly deep ship!   
    >> (A less contentious way of say dip shit).   
    >>> If you disagree, point out exactly where Kaz's code is in error.   
    >>>   
    >>> Failure to do so in your next reply or within one hour of your next   
    >>> post in this newsgroup will be taken as your official on-the-record   
    >>> admission that Kaz's code conclusively proves that the DD that HHH   
    >>> simulates will halt when simulated enough steps and therefore that   
    >>> the input to HHH(DD) specifies a halting computation.   
    >   
    > Let the record show that Peter Olcott made no attempt to show how the   
    > code posted by Kaz proves that the DDD that HHH simulates will halt.   
    > Therefore:   
    >   
    > Let The Record Show   
    >   
    > That Peter Olcott   
    >   
    > Has *officially* admitted:   
    >   
    > That Kaz's code conclusively proves that the DD that HHH simulates will   
    > halt when simulated enough steps and therefore that the input to HHH(DD)   
    > specifies a halting computation.   
      
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