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|    comp.ai.philosophy    |    Perhaps we should ask SkyNet about this    |    59,235 messages    |
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|    Message 58,653 of 59,235    |
|    olcott to Richard Damon    |
|    Re: Defining a halt decider with perfect    |
|    14 Dec 25 10:25:51    |
      XPost: comp.theory, sci.logic, sci.math       From: polcott333@gmail.com              On 12/14/2025 6:15 AM, Richard Damon wrote:       > On 12/13/25 11:42 PM, Tristan Wibberley wrote:       >> On 13/12/2025 22:31, Richard Damon wrote:       >>> ... the representation of the machine can be used to determine the       >>> behavior of the machine.       >>>       >>> How do you thing a UTM works?       >>       >> I think it's clear he thinks it doesn't, not /exactly/.       >>       >       > But his proof depends on his decider being "based on" a UTM (with       > additions) and thus qualifies to demonstrate the behavior.              The simulation of DD as an input to HHH derives       different behavior than the simulation of DD by       HHH1 because DD calls HHH in recursive simulation       and DD does not call HHH1 at all.              HHH must simulate an instance of itself simulating       an instance of DD that eventually calls yet another       instance of HHH(DD). HHH recognizes that this would       repeat forever if it did not intervene.              HHH1 simulates DD that calls HHH(DD) that returns       0 to this instance of DD.              I have been explaining this to people here for       years and they never get it. Now that I have       formulated first principles they might be able       to finally see.                     --       Copyright 2025 Olcott |
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