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|    comp.ai.philosophy    |    Perhaps we should ask SkyNet about this    |    59,235 messages    |
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|    Message 58,679 of 59,235    |
|    olcott to Mikko    |
|    The most definitive measure of the behav    |
|    16 Dec 25 11:30:01    |
      [continued from previous message]              >>> However, C rules specify what that function must return. If the function       >>> returns something other than 5 it violates C rules regardless what it       >>> is required to return.       >>       >> Likewise a halt decider is required to report on the       >> behavior that its input finite string actually       >> specifies.       >       > That does not mean anuthing without interpretation rules. Without them       > strings are merely uninterpreted strings that don't specify anything.       > Also needed is a proof that every conputation is an interpretaion of       > some string according to the inpterpretation rules.       >              (a) TMs only transform input finite strings to values       using finite string transformation rules.              (b) There exists no alternative more definitive measure       of the behavior that the input to H(P) specifies (within       finite string transformation rules) than P simulated by H.              Here is an insight that LLM Kimi suggested entirely       on the basis of the text of my first principles.              The Universal TM's Illusion: The UTM appears       to "simulate another machine," but it's really just       interpreting a string as a lookup table for state       transitions. The simulation is pure string rewriting.              > A simple way to specify the interpretaion rules is to select one       > universal Turing machine as the reference machine and saty that       > the specified interpretation is what the refernce machine does.       > The halting problem can then be formulated as:       > the halting decider shall accept if the reference machine with the       > same input halts, and       > the halting decider shall reject if the reference machine with the       > same input runs forever.       >       >> This remains true even when this finite string input       >> defines an interdependency with its decider that       >> changes its behavior.       >       > The behaviour of a Turing macine does not depend on anything other than       > its input.       >                     --       Copyright 2025 Olcott |
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