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|    comp.ai.philosophy    |    Perhaps we should ask SkyNet about this    |    59,235 messages    |
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|    Message 59,158 of 59,235    |
|    olcott to Tristan Wibberley    |
|    =?UTF-8?Q?Re=3A_G=C3=B6del=27s_G_has_nev    |
|    22 Jan 26 18:29:57    |
      XPost: comp.theory, sci.logic, sci.math       From: polcott333@gmail.com              On 1/22/2026 6:23 PM, Tristan Wibberley wrote:       > On 20/01/2026 23:08, Tristan Wibberley wrote:       >> On 18/01/2026 23:41, olcott wrote:       >>       >>> I already just said that the proof and refutation of       >>> Goldbach are outside the scope of PA axioms.       >>       >> So Richard is right that you need a truth value for not being covered:       >>       >> True(S, Goldbach) = OutOfScope       >       >       > Oh ho! but is Goldbach definable as a shortcode for a statement of the       > goldbach conjecture in PA? If there's no such statement then it's out of       > scope without a truth value for that.       >              Within proof theoretic semantics the lack       of a finite proof entails ungrounded thus       non-well-founded. My system works over the       entire body of knowledge that can be       expressed in language. Knowledge excludes       unknowns as outside of its domain.              ∀x ∈ PA ((True(PA, x) ≡ (PA ⊢ x))       ∀x ∈ PA ((False(PA, x) ≡ (PA ⊢ ~x))       ∀x ∈ PA (~WellFounded(PA, x) ≡ (~True(PA, x) ∧ (~False(PA, x))              > In addition to equality, it requires negation, either forall or exists,       > either conjunction or disjunction... but my memory says not all of those       > are available in PA in sufficient generality! Oh if only my brain worked       > as well as it once did I could work this through in a sitting, instead I       > get mentally disorganised.       >                     --       Copyright 2026 Olcott |
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