From: address@nospicedham.not.available   
      
   Kerr,   
      
   > Have I read this correctly?   
      
   I doon't think so.   
      
   > or is it (maybe I'm answering my own question) that the   
   > algorithm is based on 32bit values.   
      
   Possibly, although I do not see anything special being done with the upper   
   two bytes.   
      
   The problem is that you have degraded the hash to an 8-bit value, by   
   multiplying AL by BL.   In short, the multiplication ignores the "15" from   
   your "1505" value.   
      
   It just needs a 16 bit multiplication (AX by BX.   Mind DX though, it gets   
   overwritten).   
      
   Regards,   
   Rudy Wieser   
      
   --- SoupGate-Win32 v1.05   
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