From: luser.droog@nospicedham.gmail.com   
      
   On Monday, September 14, 2020 at 5:36:43 AM UTC-5, Alexei A. Frounze wrote:   
   > On Monday, September 14, 2020 at 2:51:34 AM UTC-7, luserdroog wrote:   
   > > On Monday, September 14, 2020 at 3:51:24 AM UTC-5, Alexei A. Frounze wrote:   
   > > > On Sunday, September 13, 2020 at 11:51:13 PM UTC-7, luserdroog wrote:   
   > > > >     // additional flags set by math operators   
   > > > > #define MATHFLAGS *fl |= ( (z&(w?0xffff0000:0xff00))     ?CF:0) \   
   > > > >                        | ( ((z^x)&(z^y)&(w?0x8000:0x80)) ?OF:0) \   
   > > > >                        | ( ((x^y^z)&0x10)                ?AF:0); \   
   > > > >                        SETPF   
   > > > >   
   > > > > I don't know where I came up with that expression for OF.   
   > > > > It's gibberish to me now.   
   > > >   
   > > > It's making sure that the result's sign is the same   
   > > > as the signs of x and y. If that isn't true, OF gets set.   
   > > > That works for addition, z = x + y,   
   > > > but not subtraction, z = x - y.   
   > > > Unless you exchange things a bit...   
   > > >   
   > > > add: z = x + y   
   > > > (z^x)&(z^y)&...   
   > > >   
   > > > sub: z = x - y   
   > > > OR, speaking in terms of addition...   
   > > > sub: x = z + y   
   > > > (x^z)&(x^y)&...   
   > > >   
   > > > IOW, for the purposes of OF calculation you need to   
   > > > exchange x and z in that formula of yours.   
   > > >   
   > > > Alex   
   > >   
   > > Thanks a bunch! It works great now. My forth can now   
   > > print numbers in any base from 2 to 36.   
   >   
   > Sorry, I hit "send" too soon without a clarification.   
   >   
   > You need to exchange x with z in MATHFLAGS for sub only.   
   > I think now you have add broken.   
   >   
      
   Ok. Thanks again. I'm parameterizing it so there's a separate formula   
   for ADDFLAGS vs SUBFLAGS.   
      
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