From: pocm@soton.ac.uk   
      
   Hello all,   
      
   I have found a conflict in parsing C99 which arises from the fact that   
   after a mult_expr a '*' (according to bison) can come up which means   
   that it can either reduce mult_expr or shift the '*' for yet another   
   multiplication.   
      
   Now, * comes up as a unary operator and in the pointer definition but   
   I can't find how or where they can follow a multiplication. Can   
   someone let me know either how to solve this shift/reduce conflict or   
   give me a concrete example where a * comes after a multiplication and   
   is not a multiplication operator?   
      
   Cheers,   
      
   --   
   Paulo Jorge Matos - pocm at soton.ac.uk   
   http://www.personal.soton.ac.uk/pocm   
   PhD Student @ ECS   
   University of Southampton, UK   
      
   --- SoupGate-Win32 v1.05   
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