XPost: comp.lang.c   
      
   Keith Thompson  wrote:   
   >   
   > So in (x + 5), x *isn't* an lvalue, even though it started out as one.   
      
   I disagree -- x *is* an lvalue, but it's converted to the value stored in   
   the object when the containing expression is evaluated.   
   --   
   Larry Jones   
      
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