From: a.moderacja@gmail.com   
      
   To construct LL(1) table M:   
   for each production A->alpha do:   
   for each terminal a from FIRST(alpha) (a<>eps) add production A->alpha   
   to M[A,a]   
   if eps is in FIRST(alpha), for each b from FOLLOW(A) add  A->alpha to   
   M[A,b]   
      
   If grammar is not LL(1), in one table position there will be more than   
   one production. Can I construct LL(k) tables simply by splitting cells   
   with more than one production? Which is algorithm to production   
   choosing ?   
      
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