On Thursday, October 24, 2013 5:38:13 PM UTC+1, Steven G. Kargl wrote:   
   > #include    
   > int   
   > main(void)   
   > {   
   >    float a, b;   
   >    a = 0.;   
   >    b = a / a;   
   >    if (a + b != b + a) printf("fubar\n");   
   >    return (0);   
   > }   
   >   
   > Can an optimizing compiler eliminate the if-statement?   
      
   It can eliminate the test because it will always be true (on IEEE   
   implementations where 0.0 / 0.0 is NaN).  It cannot eliminate the   
   if-statement because printf () should be called.   
      
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