From: DrDiettrich1@netscape.net   
      
   How is the C preprocessor assumed to handle the ## concatenation operator?   
      
   In the Windows headers I found macros like   
      #define foo(x) bar(##baz(x))   
   where an expansion into ... (baz ... doesn't make sense, because "(baz"   
   is not a valid preprocessor token. Can somebody explain the meaning and   
   handling of such constructs?   
      
   DoDi [I would guess that some macro between ( and ## expanded to   
   nothing.  Or it could just be one of those text editing errors. -John]   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)