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|    comp.compilers    |    Compiler construction, theory, etc. (Mod    |    2,753 messages    |
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|    Message 924 of 2,753    |
|    whiskey to All    |
|    Re: Grammar for roman numerals    |
|    06 Apr 07 00:00:11    |
   
   From: alex.habar.nam@gmail.com   
      
   > What about "IXIM"? Intuitively this would be 990 (-(-I+X+I)+M), but it   
   > might be calculated as (-I+X)+(-I+M) = 1008 as well.   
      
   Why (-I+X)+(-I+M) and not -(-I+X)+(-I+M) ? Following the same rule as   
   before ("a smaller number placed before a larger numeral should be   
   subtracted from it, instead of added to it") the result will be -(-I+X)   
   +(-I+M) = -(9)+(999) = 999 - 9 = 990. Since (-I+X) is smaller than (-I   
   +M), it will be substracted, not added.   
      
   --- SoupGate-Win32 v1.05   
    * Origin: you cannot sedate... all the things you hate (1:229/2)   
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