From: marc.glisse@gmail.com   
      
   Johannes Schaub  wrote:   
      
   > It is not possible to directly specify a function type with C language   
   > linkage in C++11. But in the Bloomington meeting, it was deemed useful to   
   > have 'extern "C"' linkage for alias templates possible. You can do the above   
   >   
   > as follows then:   
   >   
   >   extern "C" {   
   >     template   
   >     using FCT = R(P...);   
   >   }   
   >   
   > And formulate the function type nested in the function pointer type as   
   > follows   
   >   
   >  struct A {   
   >     // note: T is still deducible   
   >     template   
   >     A(FCT *f) { f(); }   
   >  };   
      
   I thought about that, Jonathan Wakely suggested it too, but I was   
   somehow convinced that a template alias always implied that deduction   
   would fail. Now I've thought some more about what it means, and it   
   makes perfect sense, this is a very natural solution, extending the   
   one with a typedef for the non-template case (ideally one wouldn't   
   need an alias at all).   
      
   Thanks for teaching me that template aliases have extra use that a   
   typedef inside a template class doesn't have.   
      
      
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