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   comp.lang.c++.moderated      Moderated discussion of C++ superhackery      33,346 messages   

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   Message 31,477 of 33,346   
   =?ISO-8859-1?Q?Daniel_Kr=FCgler?= to Fulvio Esposito   
   Re: sqrt(a) with 'a' being an int   
   21 Sep 11 06:29:52   
   
   3ec516dc   
   From: daniel.kruegler@googlemail.com   
      
   On 2011-09-21 00:09, Fulvio Esposito wrote:   
   > On Tuesday, September 20, 2011 3:42:23 PM UTC+2, ptyxs wrote:   
   >> #include   
   >> #include   
   >>   
   >> int main()   
   >> {   
   >>      int a = 25;   
   >>      std::cout<<  sqrt(a)<<  std::endl;   
   >> }   
   >>   
   >>   
   >> How is it ?   
   >> Thanks for any enlightenment.   
   >   
   > Vc++ 2010 gives effectively a compiler error. The reason is not for the   
   > integer type of the argument, but for ambiguity in overload resolution.   
   > there's an implicit conversion from int to all of the three types that   
   > sqrt provides an overload. And this result in an ambiguity call!   
      
   This result would be expected for a C++03-conforming compiler, but not   
   for a C++11-conforming one.   
      
   > But libstdc++ (used by gcc) has this definition in math.h   
   >   
   > template  __gnu_cxx::__enable_if<  __is_integer<   
   > _Tp>::__value, double   
   >> ::__type sin (_Tp __x)   
   >   
   > that enable sqrt for integral type resolving the ambiguity. I heven't got   
   > a copy of the standard, so I cannot say if it's required this overload.   
      
   In C++11 the example code is supposed to be well-formed, it is required   
   by [c.math] p11 which says that integer arguments shall behave as if   
   they would be provided as double values.   
      
   HTH & Greetings from Bremen,   
      
   Daniel Krügler   
      
      
      
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