From: leigh@i42.co.uk   
      
   On 03/11/2011 23:47, John Wiegley wrote:   
   >>>>>> s5n  writes:   
   >   
   >> foo( std::string("...").c_str() );   
   >   
   >> My question is simply: what is the lifetime of the string temporary object?   
   >> Does it survive until foo() returns or does it expire immediately before   
   >> foo() is called?   
   >   
   >> My point is simply to understand whether or not the above has well- defined   
   >> or undefined behaviour.   
   >   
   > The C++ Standard says, 1.9p17:   
   >   
   >   When calling a function (whether or not the function is inline), there is a   
   >   sequence point after the evaluation of all function arguments (if any)   
   which   
   >   takes place before execution of any expressions or statements in the   
   >   function body.   
   >   
   > One aspect of sequence points is that temporaries get cleaned up.   
      
   Temporaries do not get cleaned up just because we reach a sequence   
   point.  From n3242:   
      
   12.2/3   
   "Temporary objects are destroyed as the last step   
   in evaluating the full-expression (1.9) that (lexically) contains the   
   point where they were created."   
      
   Calling a function is part of a "full-expression" and a   
   "full-expression" can contain more than one sequence point.   
      
   /Leigh   
      
      
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