From: nevin@eviloverlord.com   
      
   In article ,   
    Seungbeom Kim  wrote:   
      
   > Even if you use define operator< for T, which is a member of class S,   
   > op< for S doesn't automatically get composed out of op< for T,   
      
   Well, not yet.  One is hopeful for C++1y... :-)   
      
   > but you   
   > have to manually write op< for S using op< for T, just as with   
   >   
   >     struct complex { int re, im; };   
   >   
   > op< for complex doesn't automatically get composed but you have to write   
   >   
   >     bool operator<(complex a, complex b) { /* ... */ }   
      
   Sure, but I can use other facilities to minimize the pain, as in:   
      
       bool operator<(complex const& a, complex const& b)   
       { return std::tie(a.re, a.im) < std::tie(b.re, b.im); }   
      
   --   
   Nevin ":-)" Liber     
      
      
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