4884188b   
   From: marc.glisse@gmail.com   
      
   Helmut Zeisel  wrote:   
      
   > Why does the code below not compile?   
   >   
   > VC 2010 says   
   >   
   >   error C2784: 'void f(double [m][n])' : could not deduce template   
   > argument for 'double [m][n]' from 'double [2][3]'   
   >   
   > GCC 4.5.3 says   
   >   
   >  error: no matching function for call to `f(double [2][3])'   
   >   
   > Explicitely saying f<2,3>(a) works in both cases.   
   >   
   >   
   > Helmut   
   >   
   > ===========   
   >   
   > #include    
   >   
   > template void f(double a[m][n])   
      
   You are trying to pass an array by value, that's not possible, the [m]   
   decays to a simple pointer and m can't be deduced. Notice that you can   
   call f<42>(a), the value doesn't matter.   
      
   For proper deduction, you want to pass arrays by reference.   
   template void f(double (&a)[m][n])   
      
   > {   
   >  std::cout << "m=" << m << " n=" << n << std::endl;   
   > };   
   >   
   > int main()   
   > {   
   >  double a[2][3];   
   >  f(a);   
   >  return 0;   
   > }   
      
      
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