ba9807fd   
   From: pete@versatilecoding.com   
      
   On 2012-03-15 07:07:55 +0000, Michael said:   
      
   > This has probably been asked before but...   
   >   
   > Is there a particular reason why when you define an operator ==()   
   > for a type:   
   >   
   > struct SomeType   
   > {   
   >   bool operator== (const SomeType& rhs) const { return ...; }   
   > };   
   >   
   > ... that the compiler doesn't also go ahead and implicitly define   
   > operator !=() for you?   
   >   
   > This omission has become a pet peeve of mine lately...   
   >   
      
   More generally, if you define operator== and operator<, the rest of the   
   comparison operators are defined in the namespace std::rel_ops, in the   
   header .   
      
   #include    
   using std::rel_ops;   
      
   --   
     Pete   
   Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The   
   Standard C++ Library Extensions: a Tutorial and Reference   
   (www.petebecker.com/tr1book)   
      
      
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