From: schaub.johannes@googlemail.com   
      
   I just discussed cases like "Write a perfect forwarding template that   
   calls 'make_shared'" and was told that this is not possible because   
   "make_shared" requires a single explicit argument.   
      
   I would like to spread knowledge that it is possible to write such a   
   perfect forwarder. Given a generic (template) target function "g" and a   
   perfect forwarder "f", we can write   
      
       template   
       auto f(D &&...d) -> decltype(   
                g(std::forward(d)...)   
       ) {   
         return g(std::forward(d)...);   
       }   
      
   Since "E" is the first parameter pack, it receives any explicit template   
   arguments passed to "f". This has been tested and works on GCC and Clang.   
      
      
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         [ See http://www.gotw.ca/resources/clcm.htm for info about ]   
         [ comp.lang.c++.moderated.    First time posters: Do this! ]   
      
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