From: dave@boostpro.com   
      
   on Mon Mar 26 2012, Johannes Schaub  wrote:   
      
   > I just discussed cases like "Write a perfect forwarding template that   
   > calls 'make_shared'" and was told that this is not possible because   
   > "make_shared" requires a single explicit argument.   
   >   
   > I would like to spread knowledge that it is possible to write such a   
   > perfect forwarder. Given a generic (template) target function "g" and a   
   > perfect forwarder "f", we can write   
   >   
   >    template   
   >    auto f(D &&...d) -> decltype(   
   >             g(std::forward(d)...)   
   >    ) {   
   >      return g(std::forward(d)...);   
   >    }   
   >   
   > Since "E" is the first parameter pack, it receives any explicit template   
   > arguments passed to "f". This has been tested and works on GCC and Clang.   
      
   OK... and why exactly doesn't the following work?   
      
      template   
      auto f(D &&...d) -> decltype(   
               g(std::forward(d)...)   
      ) {   
        return g(std::forward(d)...);   
      }   
      
   Seems to work for me.   
      
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   Dave Abrahams   
   BoostPro Computing   
   http://www.boostpro.com   
      
      
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