883f14a1   
   From: schaub.johannes@googlemail.com   
      
   Am 10.05.2012 23:26, schrieb William Lee:   
   { quoted mod comment snipped -mod }   
   >   
   > In C++ some primitives can be initialized using constructor-like syntax,   
   > like   
   >   
   >      int x = int(); // will zero-initialize x   
   >   
   > However, for primitives with multi-word types, I see different behavior   
   > depending on the compiler. For example:   
   >   
   >      long long ll = long long();   
   >      unsigned int ui = unsigned int();   
   >   
      
   This doesn't work because a the "type()" thing is only allowed when   
   "type" has the form of a "simple-type-specifier", wich is basically "one   
   name" / "one keyword" specifying a type. It's a syntax error. The   
   compiler that accepts it without a warning is nonconforming.   
      
   You can work it around by using some kind of "identity" template as in   
      
       template   
       using Identity = T;   
      
       long long ll = Identity();   
      
   Alternatively using the "bord tools" of C++11   
      
       long long ll = std::common_type::type();   
      
   Finally in C++11 you can use "{}", which will also result in value   
   initialization like the above cases do   
      
       long long ll{}; // will be zero-initialized   
      
      
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